8x^2-2x-15=0 How do I solve this using quadratic formula ?

Question

anonymous · Answer

the quadratic formula is +-b squareroot of b^2-4ac all over 2a. so what you do is you use 8=a, -2=b and -15=c. plug in.

anonymous · Answer

use 
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ with 
$$a=8,b=-2,c=-15$$

saifoo.khan · Answer

HELPERS!

anonymous · Answer

nusrat fateh saifoo khan is on over drive

anonymous · Answer

Aw! I wanted to use my saved copy of the quadratic.....

anonymous · Answer

- They say its 2 fractions ? Im confused .

saifoo.khan · Answer

@satellite haha, from where did u got that name? lol

anonymous · Answer

that's the plus/minus bit in the middle...

anonymous · Answer

See what I mean? U will end up with 2 answers...

anonymous · Answer

http://www.youtube.com/watch?v=TiS5xN0w4c4&feature=fvwrel

anonymous · Answer

when you have the +-, one answer will use the positive and one will use the negative.

anonymous · Answer

by some miracle this actually factors sa 
$$(2x-3)(4x+5)=0$$ so you know 
$$b^2-4ac$$ will be a perfect square and your answers will be $$x=\frac{3}{2},x=-\frac{5}{4}$$

anonymous · Answer

write it with equation forum

anonymous · Answer

(x+3)/(x+2) = 6/5
do cross multiplication 
6(x+2) + 5(x+3)
6x + 12 = 5x  + 15
transpose 5x to left hand side and 12 to right hand side 
6x-5x = 15-12
x = 3