Question

im suppose to simplify this 4y-1/2y^2-3y-2

2y-1/y-2 with the restirctions y cannot equal -1/2 and y cannot equal -2...is that right?

Answer 1

you want to simplify this:
\[\dfrac{4y-1}{2y^2-3y-2} \]
?

Answer 2

yes

Answer 3

oh but its 4^2

Answer 4

as is, the top is a clue to how youd want to try to factor the bottom

Answer 5

.... then that makes the top a difference of squares that way :)

Answer 6

still a good clue tho as to how you should try to factor the bottom tho

Answer 7

could you please retype the task? i still don't understand what exactly should be simplifyed=(

Answer 8

u wrote it right its just 4y squared. the whole thing needs to be simplfied

Answer 9

\[\dfrac{4y^2-1}{2y^2-3y-2}\]

Answer 10

\[\dfrac{4y^2-1}{2y^2-3y-2}=\dfrac{(2y-1)(2y+1)}{(2y+1)(y-2)}=\dfrac{2y-1}{y-2} y \neq-1/2\]

Answer 11

So you were right=)

Answer 12

ohh yay! thanks !