(sqrt(2)+2(sqrt(-32)))-(sqrt(8))-(sqrt(8)-(sqrt(-18))) Simplify the answers i can choice from are -sqrt(2)+11i(sqrt(2)), sqrt(2)-3isqrt(2), 3sqrt(2)-8isqrt(2),-2sqrt(2)+5isqrt(2)
you sure its 2(sqrt(-32)
could it be 32 not -32?
yeah
its -32
\[2 \sqrt{-32}-\sqrt{-18}+\sqrt{2}-\sqrt{8}-\sqrt{-18}\]
?
yes or no?
no its in the order order of how i wrote it
\[(\sqrt{2}+2\sqrt{-32})-(\sqrt{8}-\sqrt{-18})\]
\[(\sqrt{2}+2\sqrt{-32})-(\sqrt{8}-\sqrt{-18})\]
\[\left(\sqrt{2}+2\sqrt{-32}\right)-\left(\sqrt{8}-\sqrt{-18}\right)\] \[\left(\sqrt{2}+2\sqrt{-2}\sqrt{16}\right)-\left(\sqrt{8}-\sqrt{9}\sqrt{-2}\right)\] \[\left(\sqrt{2}+8\sqrt{-2}\right)-\left(\sqrt{8}-3\sqrt{-2}\right)\]
\[\left(\sqrt{2}+8\sqrt{2}\sqrt{-1}\right)-\left(\sqrt{8}-3\sqrt{2}\sqrt{-1}\right)\]
\[\left.\sqrt{2}+8\sqrt{2}i\right)-\left(\sqrt{8}-3\sqrt{2}i\right)\]
is that the answer?
you can simplify that further
could you please simplify it all the way?
\[\left(8 \sqrt{2} i+\sqrt{2}\right)-\left(2 \sqrt{2}-3 \sqrt{2} i\right)\]
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