Question

I need a differential equation, for determining an accelerated person K' (9.8 m/s^2) moving in the +Z axis, K' starts at the origin Z=0. While a point particle, is a distance of 2*(3*10^8)^2 meters from the Origin (Z=0) This point particle we will say, will start in -Z axis and will call it K. K than moves at constant velocity of (3*10^8) meters/second, Toward K' . Can someone describe this to be a function of time until K meets with K' ???

Answer 1

huhh this needs thoery of relativity and probably einstien can help u lol::))

Answer 2

I'm not entirely sure how they would like this setup as a diff eq, but the given information sets up a system of two equations. For both you would use the kinematics formula:\[Zf-Zi = Vi \Delta t + 1/2a \Delta t ^{2}\]
For person K' I assume they accelerate from rest? Giving us:
\[Zf = 1/2(9.8)\Delta t\]
For particle K, they have no acceleration. Givings us:
\[Zf = -2*(3*10^8)^2 + (3*10^8)\Delta t\]

You could use those two equations to solve for what time they are in the same position or what that position would be.