Find the volume of the solid formed by revolving the region bounded by the graphs of y=2x^2+4x and y=0 about the x-axis

Question

anonymous · Answer

ur limits of integration is gonna be where those 2 graphs intersect.

u should do horizontal lines so write ur equation in terms of x and integrate in terms of dx

the top value function is y=0

so integrate:
top value function - bottom value function

anonymous · Answer

$$\pi \int\limits_{-2}^{0}(0-(2x^2+4x))^2dx$$

anonymous · Answer

sorry its 
(top function - bottom function)^2

anonymous · Answer

http://en.wikipedia.org/wiki/Disk_method

anonymous · Answer

I'm messing up the integration. 64/15?