Question

Solve this inequality. l2x-3l(is greater than or equal to)1

Answer 1

\[|2x-3|\geq1\]
\[2x-3\geq1 \space \space or\space \space 2x-3\leq-1\]

Answer 2

Thank you!

Answer 3

Wait..... Isn't the negative three supposed to be a plus?

Answer 4

no, it should be negative

You have to solve for x but I trust you can do it

Answer 5

Yeah, I can, I just thought it was positive because anything negative in absolute value turns positive

Answer 6

The absolute value is over the whole thing not just the 3
if it were
\[2x+|-3|\geq1\]
then -3 would turn positive

Answer 7

oooooh, so if it's by itself then it turns pos., but if it includes other numbers then it stays the same?

Answer 8

\[|-(2x-3)|=(2x-3)\]

Answer 9

2x+3???????

Answer 10

So when we say
\[|2x-3|\geq1\]

What we are really is saying is that
\[(2x-3)\geq1\]
and
\[-(2x-3)\geq1\]

Answer 11

\[-(2x-3)\geq1\]
When we divide both side by -1 we switch the inequality sign
\[(2x-3)\leq-1\]

Answer 12

hmmmmm, thx anyway. I'm so confused

Answer 13

So the answers for the original two would be...... x(is greater than or equal to)2 OR x(is greater than or equal to)1?????

Answer 14

http://www3.wolframalpha.com/Calculate/MSP/MSP208519gd5029be0083ce00002271bc1d6b5822ab?MSPStoreType=image/gif&s=6&w=310&h=36

Answer 15

I don't get what that means so can you tell me yes or no please?

Answer 16

\[x\geq2\]or
\[x\leq1\]

Answer 17

YAY! I GOT IT RIGHT! THANK YOU!