Suppose that each point (x, y) in the plane, both of whose coordinates are rational numbers, represents a tree. If you are standing at the point (0, 0), how far could you see in this forest?
wow <.< where are you getting these from? o.O
my textbook. I was looking through it and I found this whole problem solving section.
I wouldn't think you could see anywhere
because the rational numbers are dense right?
er..."dense", idk, i read it in an analysis book somewhere lol
something like "in between any two real numbers there is always a rational number"
say your line of sight is along the function f(x)=ax then for e>0 the interval (0,e) will contain an irrational number..and thus a tree will be in your immediate line of sight
for all a
oops looking at it backwards
Joe? & Zarkon http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e3231b90b8ba7b2da415e84
the argument still works though, just for rationals
replace irrational with rational
for some reason i thought a tree was at irrational points ;)
now I think it might not work...jas...let me think
what about the line of sight ... \[f(x)=\pi x\]
x and y cant both be rational at the same time
so you can see as far as you want in that direction
The way i had started thing about the problem was that last statement i made, "Between any real numbers there is a rational number." If i have 2 trees some distance e apart, i would try to look in between them. But there would have to be another tree in between them. So i try to look in between those trees, but there would also be a tree in between them. So on and so forth~
but for any pair of points that satisfy the line of sight \[y=\pi x\] there are no rational pairs...so nothing is blocking your sight in that direction
i take back my statement, i agree with yours Zarkon.
cute problem
i'm not sure that I fully grasp the problem...
any help?
can you be more specific?
well I thought that the coordinates of (x, y) are both rational numbers, but then you said that there are no rational pairs... anyways that confused me
Can you help me PLEASE!
well we put a tree for any pair (x,y) that are rational but, using the line of sight from above \[y=\pi x\] we get the points \[(x,\pi x)\] is this case it is impossible for both the x and y coordinate to rational if x is irrational the there is not tree at (x,y) if x is rational then y is irrational and again there is no tree at (x,y) does that help?
well I understand that, but where did you get the \[y = \pi x\]?
it just came to mind. it was a function that gave me what i needed. I could have used others
let a be any irrational number then the line of sight y=ax has no trees by the same argument above
I use ax since it is a line that goes through the point (0,0)...which is the point we are standing at
oh ok thank you so much for the help! :)
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