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Mathematics 18 Online
OpenStudy (anonymous):

Suppose that each point (x, y) in the plane, both of whose coordinates are rational numbers, represents a tree. If you are standing at the point (0, 0), how far could you see in this forest?

OpenStudy (anonymous):

wow <.< where are you getting these from? o.O

OpenStudy (anonymous):

my textbook. I was looking through it and I found this whole problem solving section.

OpenStudy (zarkon):

I wouldn't think you could see anywhere

OpenStudy (anonymous):

because the rational numbers are dense right?

OpenStudy (anonymous):

er..."dense", idk, i read it in an analysis book somewhere lol

OpenStudy (anonymous):

something like "in between any two real numbers there is always a rational number"

OpenStudy (zarkon):

say your line of sight is along the function f(x)=ax then for e>0 the interval (0,e) will contain an irrational number..and thus a tree will be in your immediate line of sight

OpenStudy (zarkon):

for all a

OpenStudy (zarkon):

oops looking at it backwards

OpenStudy (anonymous):

the argument still works though, just for rationals

OpenStudy (zarkon):

replace irrational with rational

OpenStudy (zarkon):

for some reason i thought a tree was at irrational points ;)

OpenStudy (zarkon):

now I think it might not work...jas...let me think

OpenStudy (zarkon):

what about the line of sight ... \[f(x)=\pi x\]

OpenStudy (zarkon):

x and y cant both be rational at the same time

OpenStudy (zarkon):

so you can see as far as you want in that direction

OpenStudy (anonymous):

The way i had started thing about the problem was that last statement i made, "Between any real numbers there is a rational number." If i have 2 trees some distance e apart, i would try to look in between them. But there would have to be another tree in between them. So i try to look in between those trees, but there would also be a tree in between them. So on and so forth~

OpenStudy (zarkon):

but for any pair of points that satisfy the line of sight \[y=\pi x\] there are no rational pairs...so nothing is blocking your sight in that direction

OpenStudy (anonymous):

i take back my statement, i agree with yours Zarkon.

OpenStudy (zarkon):

cute problem

OpenStudy (anonymous):

i'm not sure that I fully grasp the problem...

OpenStudy (anonymous):

any help?

OpenStudy (zarkon):

can you be more specific?

OpenStudy (anonymous):

well I thought that the coordinates of (x, y) are both rational numbers, but then you said that there are no rational pairs... anyways that confused me

OpenStudy (anonymous):

Can you help me PLEASE!

OpenStudy (zarkon):

well we put a tree for any pair (x,y) that are rational but, using the line of sight from above \[y=\pi x\] we get the points \[(x,\pi x)\] is this case it is impossible for both the x and y coordinate to rational if x is irrational the there is not tree at (x,y) if x is rational then y is irrational and again there is no tree at (x,y) does that help?

OpenStudy (anonymous):

well I understand that, but where did you get the \[y = \pi x\]?

OpenStudy (zarkon):

it just came to mind. it was a function that gave me what i needed. I could have used others

OpenStudy (zarkon):

let a be any irrational number then the line of sight y=ax has no trees by the same argument above

OpenStudy (zarkon):

I use ax since it is a line that goes through the point (0,0)...which is the point we are standing at

OpenStudy (anonymous):

oh ok thank you so much for the help! :)

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