Question

ok guys tell me if i got this one right
solve 2x^2=10
find the x intercepts of f(x)= 2x^2-10

Answer 1

solutions are \[(\sqrt{5},-\sqrt{5})\]

Answer 2

intercepts are (5,0),(-5,0)

Answer 3

The first answers are correct. Your intercepts are wrong. When you solve for x you get -sqrt(5) and sqrt(5).

y =2x^2-10

When finding the x intercept, y is 0. (which is what you got in the first question)
When finding the y intercept x = 0
y = 2x^2 -10
y = 2x0^2 -10
y = -10

Your intercepts are \[(\sqrt{5}, 0) and (\sqrt{-5},0)\]

Answer 4

That's your x intercepts, and your y intercept is -10