Question

Factor the polynomial completely.
x^3+x^2+2x-4
Using synthetic division.

Answer 1

I'm here lol xD ; )

Answer 2

whats synthetic division ? can't I use normal factorization ! O_o

Answer 3

Its like long division, but faster and simpler.

Answer 4

If I'm allowed Normal Factorization

Ok I get it ! Different Region ...Different Terms ..It's Fast but not on Open Study ; )

Answer 5

\[x^3 + x^2 + 2x -4 = 0 \]That's the Equation Right ?
Now When I put 1for x ! I get \[L.H.S =R.H.S\]

Answer 6

So It Implies 1 is a root for the Equation ...

Answer 7

Then I Divide
\[\frac{(x^3 + x^2 + 2x - 4)}{x - 1} \]

Answer 8

I just checked and wow! How did I miss that!? I swear I checked one, but thanks! Now I can finish it. :)

Answer 9

__________________________
x - 1 | x^3 + x^2 + 2x -4 |x^2 +x + 4
x^3 - x^2
___________
2x^2 + 2x
2x^2 - 2x
_____________
+ 4x - 4
4x - 4
_________
0

There You Go YOU Have a Equation Again

\[ x^2 + x +4=0\]
Solve it To Get the other two Roots

Answer 10

\[x = \frac{ -1 \pm \sqrt{ 1 -4}}{2}\]
\[x = \frac{-1 \pm i \sqrt{3} }{2}\]

Which Gives Us Complex Roots or Imaginary Roots

Thus Roots are \[1,w,w^2\]

Answer 11

Did you get it ? : )