Find the equation of a line which passes through point (-7, 1) and is parallel to the line formed by the equation y = 6x + 8. Express it in slope-intercept form.

y = - 1 x + 43
y = 6x + 43
y = 6x - 43
y=(1/6)x+43

Question

Find the equation of a line which passes through point (-7, 1) and is parallel to the line formed by the equation y = 6x + 8. Express it in slope-intercept form.

y = - 1 x + 43 
 y = 6x + 43  
y = 6x - 43 
y=(1/6)x+43

chaise · Answer

y = 6x+8

If the line is parralel, then they have the same gradient, with a different y intercept (8).

So, if the second line runs through (-7,1) we can substitute these values into the "y = mx+b" with m = 6 (same gradient as before)

y = mx+b
1 = 6x-7+b
1 = -42 + b
43 = b

Your y intercept of this equation is 43. We can now put this all together to form the equation:

y = mx+b
y = 6x+43.

Does this make sense? Do you need further explanation?