Find the equation of a line which passes through point (1, 7) and is perpendicular to the line formed by the equation -2x + -10y = -9. Express it in slope-intercept form y = 5x - 2 y= -5x - 2
y = -5x + 2 y = 5x + 2

Question

Find the equation of a line which passes through point (1, 7) and is perpendicular to the line formed by the equation -2x + -10y =  -9. Express it in slope-intercept form    y = 5x - 2  y= -5x - 2 
 y = -5x + 2    y = 5x + 2

anonymous · Answer

$$-2x-10y=-9$$?

anonymous · Answer

y = 5x +2

anonymous · Answer

slope is 
$$-\frac{1}{5}$$ so your slope is 5

anonymous · Answer

so it is either 
$$y=5x-2$$ or 
$$y=5x+2$$ and since (1,7) is on the line it must be 
$$y=5x+2$$ since that is the one that works