How many three-digit numbers can be formed using the digits 0 and 7? Repeated digits are allowed.
how many digit are there between 0 to 7?
8
making a tree diagram makes this thing huge
but its only the digits 0 an7 so that doesnt matter how many are in between
so we have to think of it logically; we have 8 choices; which have 8 choices, making 8*8 = 64 choices we have another 8 choices for each of those; 64*8 = 8^3 8*8*8 = 8^3 = number of options total
Oh, it is just 0 and 7 so you have two choices for each digits 2 * 2 *2 =8
think of a tree that has 8 branches, named 01234567 each branch has 8 more branches ... with 8 more branches extending from thos as well
.... and the 0 i spose makes for complication lol
its only the digits 0 and 7
there are 000 to 099 that we can omit I spose?
so its not as complicated as we think
I believe my last response was right
But we have two digits and 3 spaces ..
why would it be 2 * 2* 2?
lol ... this belongs in the writing section ;) maybe
two choices for first digit 0,7 two choices for second digits 0,7 two choices for third digits 0,7 2*2*2=8
000 007 070 700 077 707 770 777 is that all of them?
yeah got it
aint that 3C2 as well?
okay thank you!
Not combination or permutation because numbers are allowed to repeat
yeah
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