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find indicated term 3rd, (a+b)^{6}
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so you are going to expand using the binomial theorem. The kth term of: \[(a+b)^n\] is : \[\left(\begin{matrix}n \\ k-1\end{matrix}\right)a^{n-(k-1)}b^{k-1}\] so in your problem, n = 6, and k = 3, so just plugging in numbers we get: \[\left(\begin{matrix}6 \\ 3-1\end{matrix}\right)a^{6-(3-1)}b^{3-1} = 15a^4b^2\]
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