Question

You have seen that the total number of lights in a triangular lighting rig is given by T(n) = n2/2 + n/2, while T(n+1) = n2/2 + 3n/2 + 1. If T(n) times T(n+1) = f(n), what is the reduced form of f(n)?

Answer 1

u shud be able to do this. factorize T(n) and T(n+1) and then multiply.

Answer 2

g(n) = g(n-1) + n?

Answer 3

T(n) = n(n+1)/2
T(n+1) = (n+1)(n+2)/2
T(n)*T(n+1) = f(n)
so multiply T(n) and T(n+1) and calculate f(n)...

Answer 4

g(n) = g(n -1) + 1 ?

Answer 5

where did you get g(n) from?

Answer 6

when i solved for it

Answer 7

oh i was on wrong problem

Answer 8

i got f(n)=n^4=n^2/2+n^2/2+n/2

Answer 9

its not correct. when u multiply T(n) and T(n+1) u get f(n) = n(n+1)^2(n+2)/4
U can expand it and arrive at f(n) = (n^4+4n^3+5n^2+2n)/4. Its just simple multiplication.

Answer 10

didi u ever figure out the awnser