What is the maximum number of turns for the graph of

ƒ(x)=-4x^4-3x^3+5x-27

Question

What is the maximum number of turns for the graph of

ƒ(x)=-4x^4-3x^3+5x-27

anonymous · Answer

with no other information it is 3, one less than the degree.

saifoo.khan · Answer

3.

anonymous · Answer

The max is always n-1.

anonymous · Answer

i liked megan fox better than superman

saifoo.khan · Answer

Aah, this is just coz of "S"
coz S = SaifoO! ;)

saifoo.khan · Answer

i will chng that in some days.

anonymous · Answer

What doy you mean by 'turns'? Do you mean solutions or zeros?

myininaya · Answer

i don't know what you by turns either

myininaya · Answer

mean by turns either*

anonymous · Answer

Points at which the derivative changes sign.

myininaya · Answer

maybe

anonymous · Answer

It's going one way, and it turns around ;p

myininaya · Answer

right 
is that what you mean kassia?

myininaya · Answer

do you know how to find f'?

myininaya · Answer

we need to find f' first
and then find where the turns happen (where f'=0)

myininaya · Answer

so i assume you got this since you aren't saying anything

anonymous · Answer

I also call them "turning points" (bit old fashioned, I know...)

myininaya · Answer

and i guess you really dont have to find f'
you could just say the max is 3 sinces the degree of the polynomial is 4
the max amount of turns is the degree -1

anonymous · Answer

y'all bein' silly. you don't need calc for this