Question

3n-40=1/2n+33 i got
n = 1/(-73-sqrt(5335))

Answer 1

how did u get that?

Answer 2

neither of the n's are squared so how'd u get sqrt?

Answer 3

it came out to 25 and i got that by trying to copy and paste it onto a caculator

Answer 4

o i c what happened. is the equation
3n-40=(1/2)n+33
or
3n-40=1/(2n)+33

Answer 5

?

Answer 6

is it "a half of n" or "1 divided by 2n"?

Answer 7

half

Answer 8

\[3n-40 =1/2n+33 = (1+66n)/2n\]
\[2n*(3n-40)=1+66n\]
\[6n ^{2}-80n-66n-1=0\]
\[6n ^{2}-146n-1 =0\]
now solve for n using the quadratic formula

Answer 9

3n-40=(1/2)n+33
2(3n-40)=2((1/2)n+33)
6n-80=n+66
6n-n-80=n-n+66
5n-80=66
5n-80+80-=66+80
5n=146
n=146/5
or
29+1/5

Answer 10

thank you for steps both of you