x+y+x=53 3x-2y+z=69 -x+2y-z=-59 i got (68, -24, 9)
Hmm... I actually got different answers. I might be wrong though. You want to work on this together?
ok
i did y
Oh wait...
x+y+x=53 <--- are you sure it's two x's ? 3x-2y+z=69 -x+2y-z=-59
last one a z my bad
Ah ok. This will change up my answer a little. Regardless, here's what we shall do: equation 1 = x+y+z=53 We want to solve what Y is first, so... let's put y by itself. y = -x - z + 53
x
Mmk. 3x-2y+z=69 3x = 2y - z + 69 x = (2y - z + 69)/3
To be honest, though... z would be A LOT easier to use. Should we do that instead?
Your choice.
ok
Awesome. Equation 2: 3x-2y+z=69 z = -3x + 2y + 69 So far so good?
yea writing the steps down
Okie dokie. I'll go ahead and begin explaining the next step. We're going to combine this last equation into the equation we made earlier. y = -x - z + 53 This was equation 1 in the form of y = blahblah z = -3x + 2y + 69 This was equation 2 in the form of z = blahblah We're going to create what I call equation 1.2 (meaning equation 1 combined with 2) y = -x - (-3x + 2y + 69) + 53 Let me know if this step made sense. It's important that this makes sense before we do anything else.
ok i dont get this step
Okie dokie. Thanks for letting me know. ^_^ Remember how equation one was written to say y = -x - z + 53 , right?
And how we made equation 2 say z = -3x + 2y + 69 ?
yea
Alright. Because equation two says, "the letter z is exactly "-3x + 2y + 69", we can replace any z that we see with "-3x + 2y + 69". Does that statement make sense?
yea
Snazzy. So what we did is go back to equation 1: y = -x - z + 53 And replaced the z with what?
-3x + 2y + 69
Excellent. So we're left with y = -x - (-3x + 2y + 69) + 53 right?
(The stuff in parentheses replacing the original z that was there)
yea i see
Alright. Now we're going to distribute that minus that's in front of our parentheses.
y = -x - (-3x + 2y + 69) + 53 y = -x +3x -2y - 69 + 53 Looking good so far?
yea and sorry idk why it keeps putting i dont get this step every time i post
Yeah, I noticed lol. It's ok, this site does that kind of stuff. :P
Now we combine similar terms: y = -x +3x -2y - 69 + 53 y = 2x -2y - 16 (be careful that you don't accidentally say you have 4x) 3y = 2x - 16 So far so good?
yea
Awesome. Now, we're going to want to note this equation, because it's missing a Z, which is great. So, let's call it equation 1.2 (as in equation 1 mixed with equation 2) ***** Equation 1.2 ******* 3y = 2x - 16 I'll show you in a few moments why we are going to like this equation.
Alright. Last thing we want to do is get x by itself in equation 3. Equation 3: -x+2y-z=-59
-x+2y-z=-59 2y -z + 59 = x x = 2y - z + 59 Makes sense so far?
yea and thanks for going slow I starting to get it
Not a problem! I'm just happy that you're willing to learn instead of just demanding the answer. :D
Alright, so remember in our awesome equation 1.2, we only had x and y?
yep
3y = 2x - 16 What would happen if we plugged in x = 2y - z + 59 You should notice a problem that would occur.
As in, 3y = 2x - 16 3y = 2(2y - z + 59) - 16
we can simplify the y?
We technically can, but there's a bigger problem. I'll give you a hint: "Alright, so remember in our awesome equation 1.2, we only had x and y?" Why do you think I asked that question? :P
In other words, we started with 3y = 2x - 16 where there were only two variables. But once we put in our x = 2y - z + 59, we have a problem.
z came into the equation?
That's right. How do you think we will make z go away and replace it with something nicer?
ok i dont get this step
I would say cancel it out but I don't know how that would work
Well, we did something earlier that let us get rid of the original z. Do you recall what we did?
Hint: Scroll up about halfway to where I said, "Snazzy. So what we did is go back to equation 1: y = -x - z + 53 And replaced the z with what?" And you answered it correctly.
oh we replaced z with -3x + 2y + 69
Exactly. :D So here's what we have now, after switching out x: 3y = 2(2y - z + 59) - 16 What will our new problem look like after we replace z?
Hint: Make sure that you put the stuff that's replacing z in parentheses, or your negative won't carry through correctly.
um 3y=2(2y-(-3x=2y+69)+59)-16?
3y = 2(2y - (-3x + 2y + 69) + 59) - 16
Though, I'm guessing your keyboard messed up on that = instead of +, right?
yea i think
Awesome. We're almost done! Now we just begin simplifying. 3y = 2(2y - (-3x + 2y + 69) + 59) - 16 3y = 2(2y +3x - 2y - 69 + 59) - 16 So far so good? Please double check this to be safe. It'd suck if we get messed up on this step.
it looks good when i went over it i didnt see anything that looked wrong
Awesome. 3y = 2(2y +3x - 2y - 69 + 59) - 16 3y = 2(0y + 3x - 10) - 16 3y = 0y + 6x -20 - 16 3y = 6x -36 So far so good?
Note that the 0y can just be removed since "no y's" is the same as "nothing".
ok
Awesome. Now, notice there's something we can do on this step to make it a lot prettier. What do you think that is?
(Think greatest common factors)
3y = 6x -36
something with 6 and 36?
Something even easier. Hint: It has to do with a 3.
3 and 6?
We can just divide everything by 3, right?
yea
3y = 6x -36 y = 2x - 12 Looks a lot nicer, ya?
yea it does
Alright, here's where it gets a little challenging. I'm going to let you figure this out (I'll give hints if you need them). We want to replace x with something that has just constants and a y, so that we can have only one variable. You know that we have to have an equation in the form of "x = yblahblah". Which equation will we use to get such a thing? I'll give you a hint if you need it.
In other words, besides the one we're working with right now, which equation has only x's and y's? We do NOT want any z's messing with us.
3y = 6x -36?
But that's the same equation we're working with. If we put that in there, we'd get something that will lead us to 0=0 because everything would cancel out. We need a different equation.
Hint: I said something about a "super awesome equation" earlier, right? ;) Now's her time to show us her magic!
I didnt see it. Gimmy min let me look through my notebook.
I'll go ahead and give it to you. 3y = 2x - 16 This was that special 'equation 1.2' that had only two variables. Remember that one?
yea
Ok. So what are we going to do to that equation (3y = 2x - 16) to help us solve (y = 2x - 12) ?
plug y in?
Here's a useful hint: NORMALLY, you want to get it in the form of x = blah blah. But in this case, you can find a similar variable in both equations. Do you see anything repeated exactly the same?
Hmm.... actually, we could do that too. I'll show you both ways.
Method 1: (what I was planning on doing) Since 2x appears in both equations, you could do this: given: (3y = 2x - 16) and (y = 2x - 12) 3y = 2x - 16 3y + 16 = 2x 2x = 3y + 16 Since 2x = 3y + 16, we can change equation 1.2 from (y = 2x - 12) into (y = 3y + 16 - 12) Then simplify into (y = 3y + 4) (-2y = 4) y = -2 Does that make sense?
yea
Method 2: (your easier way :P) given: 3y = 2x - 16 and y = 2x - 12 Plug in y into the first equation: 3(2x - 12 ) = 2x - 16 6x - 36 = 2x - 16 4x = 20 x = 5
Oooo nice! Do you see what happened?
you found what x = so no you can plug it in or something else?
Yup! Let's use the easiest equation for that. x+y+x=53
Oops. I copied it from the original question. Here's the correct one: x+y+z=53
so be 5+y+z=53?
But we also found y earlier, remember?
-2
Exactly.
5+-2+z=53
Perfect. So 3 + z = 53. Now put in the last jigsaw on this beautiful puzzle. :P
z=50 but thats not to big?
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