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how do i determine f^-1(x) when f(x)={(3,5)(2,4),(1,7)}
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So when i put solutions to f(x) in the form of points (x,y), im saying: f(x) = y, i give the function an 'x', it gives me a 'y' f inverse's job is if i give it a 'y', it will give me the 'x', soit should be something like: \[f^-1(y) = x\]
whoops: \[f^{-1}(y) = x\]
soits the inverse of what
So if f(3) = 5 (from your problem), then \[f^{-1}(5) = 3\] and the point it would create is (5,3)
so i do that for all three of the sets
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yes :)
thanks
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