Explain, in complete sentences, how you would completely factor 20x2 - 28x - 48.
4 (x+1) (5 x-12)
saifoo.khan, I know how to factor, but I just guess and check, is there some way to do it faster? Or not really?
there's something called the ac factoring method
Epaema, sorry i didnt get wht u said! sorry!
I'm so confuzzled, haha
Why?
Never mind. Haha! :D
I think I'm supposed to use the grouping method :/
so it's called "the ac factoring method"?
thts also grouping!
thts kindda shortcut.
Ok, so it's called "the ac factoring method"?
Yes.
There are a lot of different methods. For this one I would look at the numbers first. It should be apparent that you can factor out a 4 from the numbers: \[20x^2-28x-48 \Rightarrow 4(5x^2-7x-12)\] The grouping comes into play because we notice here that 12 - 5 = 7, so we get: \[4(5x^2-7x-12) \Rightarrow 4(5x^2+5x-12x-12) \Rightarrow 4(5x(x+1)-12(x+1))\] \[4(x+1)(5x-12)\]
er, that should be " ...we notice here that 5x - 12x = -7x, so we..." my bad.
Thank you!
I still don't get the grouping part..........
idk why didnt u.
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