Question

Let N = 999 999 999 999 999 999.
How many N's are there in N^2 ???

Answer 1

N

Answer 2

there is N amount of N's

Answer 3

If u say 1 u will be in trouble....

Answer 4

Consider N = 9
N = (10 -1) => N^2 = (10-1)^2 = 10^2 +1 -2*10*1= 101 - 20 = 81
That is 101 has 1 zero
and 20 has 1 zero
No 9's in N^2

Consider N =99
N = (100 -1) => N^2 = (100-1)^2 = 100^2 +1 -2*100*1= 10001 - 200 = 19801
That is 10001 has 3 zero
and 20 has 2 zero
Number of 9's in N^2 = 3 zeros - 2zeros = 1 9's
replicate it for
N = 999 999 999 999 999 999
18 => 9's are there in N
Therefore 17 9's will be there in N^2

Answer 5

so u want the amount 9's that will b predicted by that pattern?

Answer 6

U didn't ask for 9's, u asked for N's....

Answer 7

im thinking 1

Answer 8

I already said if he said that, I would just conclude, well u know...

Answer 9

Sorry guys its how many 9 's are there in N^2???its a typo error..

Answer 10

I have concluded from this and your other questions that you are not serious.

Answer 11

Actually, I have reached some other conclusions as well, the rules require me to be polite though.

Answer 12

I just posted the question which I am solving or trying to solve.

Answer 13

You posted the wrong question and waited for many posts to correct it.

Answer 14

I apologies for that...

Answer 15

sorry its 17 9's, one 8, one 1 and the rest are zeros