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Mathematics 19 Online
OpenStudy (vishweshshrimali5):

someone please help me fastttttttt Its very urgent

OpenStudy (anonymous):

U need an urgent answer? OK, no.

OpenStudy (vishweshshrimali5):

1) The dissociation constant of a substituted benzoic acid at 25' C is 1*10^-4. The pH of 0.01 M soln of its sodium salt is 2. The solubility of Mg(OH)2 is a moles/litre. The solubility product under the same condition is a) 4S^3 b) 3S^4 C) 4S^2 d) S^3

OpenStudy (vishweshshrimali5):

estudier this is the question

OpenStudy (anonymous):

AArgh, chemistry...

OpenStudy (vishweshshrimali5):

yes please

OpenStudy (anonymous):

@vish post it in biology section there are many people there they can answer ur question easily

OpenStudy (vishweshshrimali5):

but this one is off IIT and is very hard to answer (chem.)

OpenStudy (anonymous):

number 2 is a i think

OpenStudy (anonymous):

cant do the first but good luck with that

OpenStudy (vishweshshrimali5):

Thanks

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