hi class can you show me how to prove that AnB=BnA ... im trying to do it but i don't understurd
Is this Commutative multiplication or what?
What are A,n and B? Numbers?
an n which is between A AND B is the intersection
Ah, sets...
A and B are sets of numbers while n is representing intersection
Sorry, used to the upside down U
So u want to show that if the two circles change places, the intersection stays the same, is that right?
yes that it
I have to say this strikes me as being rather obvious, I guess that is not what u want though. Assume there is a set C, subset of A and subset of B, containing all the elements common to A and to B then A n B = C and B n C = C Is that any good?
ok i never got it at first .the meaning of the intersection .but what you have said i can relate the with the once on the book now .thanks
ur welcome.
let x b contained in A or B (BY DEFINATION OF UNIONS) this means is equivalent BuA (BY COMMUTATIVE LAW)
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