Find the equation of the line perpendicular to the line 3x=y-5 and passing thruogh the point
(7, 21)

Question

Find the equation of the line perpendicular to the line 3x=y-5 and passing thruogh the point 
(7, 21)

amistre64 · Answer

perp lines swap the coeffs of x and y then changes the sign of one of them

amistre64 · Answer

3x = y - 5 ; perps to

-x = 3y - 5 ; but the 5 is useless, AND this is not in any particular line format :)

amistre64 · Answer

drop the f and calibrate with the given point

amistre64 · Answer

f means 5 for some reason :)

amistre64 · Answer

-x = 3y - 5 

-x = 3y - n

-(7) = 3(21) - n 

n = 63 + 7

n = 70

-x = 3y + 70 ...

amistre64 · Answer

format it to whatever line format they will accept

anonymous · Answer

y=-1/3(x)+70
use thi method
y=mx+c
sub:x and y
21=-1/3(7)+c
c=70

since the m of the original equation is 3 this means for perpendicular line will be -1/3