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Find the equation of the line perpendicular to the line 3x=y-5 and passing thruogh the point (7, 21)
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perp lines swap the coeffs of x and y then changes the sign of one of them
3x = y - 5 ; perps to -x = 3y - 5 ; but the 5 is useless, AND this is not in any particular line format :)
drop the f and calibrate with the given point
f means 5 for some reason :)
-x = 3y - 5 -x = 3y - n -(7) = 3(21) - n n = 63 + 7 n = 70 -x = 3y + 70 ...
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format it to whatever line format they will accept
y=-1/3(x)+70 use thi method y=mx+c sub:x and y 21=-1/3(7)+c c=70 since the m of the original equation is 3 this means for perpendicular line will be -1/3
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