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∬_D y d A D is between x=y^2 -1 & x=-y^2+2y+3
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\[\int\limits_{-1}^{2}\int\limits_{y^2-1}^{-y^2+2y+3}y\,dx\,dy=\frac{9}{2}\]
Zarkon, shouldn't the outter integral be: \[\huge\int\limits_0^3\] Instead of: \[\huge\int\limits_0^2\]
solve y^2 -1=-y^2+2y+3 you get y=-1 and 2
Ahhhh gotcha lol
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