Question

how do i factor quadratics when the leading coefficiant isnt 1x EX: 9X-6x+1

Answer 1

a few ways .... quadratic equation might be the simplest, and by simplest I mean not the simplest lol

Answer 2

wats a way other than quadratic formula

Answer 3

other ways are to set up the factors, if they can be integered like this:

(x+m/a) (x+n/a) such that:

ax^2 +bx + c = 0 factors as:

a*c = m*n

m+n = b

Answer 4

reduce m/a and n/a as far as they will go; and if they are still a fraction, put the bottom in front.

(ax + m) (ax + n)

Answer 5

if we use your example we have:

9x^2-6x+1 = 0

9(1) = 9, factors of n are:

1,9; 9+1 = 10
-3,-3; -3-3 = -6

(x-3/9) (x-3/9), simplify

(x-1/3) (x-1/3) ; put the bottoms in front

(3x-1) (3x-1), or simply (3x-1)^2

Answer 6

*factors of 9 are ... :)

Answer 7

thanks takes me awhile but ill get it