help me answer these questions...Picture will be posted in a few seconds. Thanks

Question

anonymous · Answer

attachment

anonymous · Answer

ktugrew please look at previous post.  it was somewhat incomplete

anonymous · Answer

any function that changes from concave up to concave down at (-1,2) will do. The first derivative must be undefined for a vertical tangent line (0 is horizontal). the second derivative must be undefined also, because it represents the slope of the slope of a function which is going to infinity at -1.  The last one is impossible

anonymous · Answer

picture something like 
$$f(x)=\sqrt[3]{x+1}+2$$

anonymous · Answer

im trying..lol..but I'm not getting it