In a chemistry class, 6 liters of a 4% silver iodide must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% are needed?

Question

In a chemistry class, 6 liters of a 4% silver iodide must be mixed with a 10% solution to get a 6% solution.  How many liters of the 10% are needed?

anonymous · Answer

.04(6L)+.1(x)=.06(6+x)
4(6)+10x=6(6+x)
24+10x=36+6x
4x=12
x=3 liters

anonymous · Answer

ur quick. i just finished he is right

anonymous · Answer

thanks

anonymous · Answer

you are great!!!

anonymous · Answer

what he did was compare the percentage of acid
04(6L)+.1x is the amount of acid so if we divide that by the amount of solution:
6+x we get the percentage which should b equal to 6% so:
(.04(6)+.1x)/(6+x)=.06

anonymous · Answer

You make it sound so easy, thanks

anonymous · Answer

lol it takes practice