Question

Find the horizontal asympote, if any, of the rational function.

f(x)=5/x^2+1

Answer 1

y=0 is a horizontal asy

Answer 2

y=0 is a vertical asymptote. There's a horizontal one at y=1

Answer 3

just divide x^2 on both top and bottom
5/x^2 goes to 0 as x goes to infinity

Answer 4

\[y=\frac{5}{x^2+1}?\]

Answer 5

\[5/x ^{2}+1\] is what I read, which explains the discrepancy

Answer 6

did you mean y=5/(x^2+1) or y=5/x^2+1
i just assumed he doesnt write parenthesis like the last problem

Answer 7

you could be right

Answer 8

If it reads as myin read it, there are no asymptotes. If it reads as I read it, there's a vert at x=0 and a horizont at y=1

Answer 9

the original problem doesn't have parenthesis
its written f(x)=5/x^2+1

Answer 10

myininaya wrote it correct

Answer 11

so the answer is "none"

Answer 12

\[y=\frac{5}{x^2+1}\]
you can write that as 5/(x^2+1)
but if you write it as y=5/x^2+1, you mean\[y=\frac{5}{x^2}+1\]
so we have \[y=\frac{5}{x^2+1}\] we have y=0 is a horizontal asymptote

Answer 13

yes, the way that you wrote it the first time is the correct way to write the problem.

Answer 14

lol