Question

if michael jordan has a vertical leap of 1.29 m, what is his take-off speed and his hang time (total time to move upwards to the peak and then return to the ground)?

Answer 1

\[v ^{2}=u ^{2}+2as\]
\[0=u ^{2}+ 2\times (-9.8) \times 1.29\]
\[u=5.0283m/s \]
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\[v = u + at\]
\[0 = 5.0283 -9.8 \times t\]\
\[t = 0.5130 \sec\]
Total time = 2t = 1.0261 sec