Question

Find the equation of a straight line that passes through

(1, -2) and (-1, 4)

Using m= y2 - y1
-------
x2 - x1

I done so far: y = -3x + c, how do i find c? Seeing as I have to find the equation.

Any help please?! Thanks

Answer 1

all my lines are straight.

Answer 2

the slope is = (4+2)/(-1-1) =-3
Now I choose the point (1,-2) and applying the formula y-y1=m(x-x1) I got
y+2 = -3(x-1)
y+2=-3x+3
3x+y-10=0

Any question, please ask

Answer 3

Thank you very much ermunrradtvamg!!!!, this is just what I needed, I was not aware of the second formula and I was starting to get extremely annoyed with this question. You have explained perfectly!

Answer 4

UW

Answer 5

Actually sorry one question the end shouldn't it be y = -3x + 1?

Seeing as y + 2 = -3x + 3
The 2 will move to the other side and it will become subtract from that to equal:

y = -3x + 1