Mathematics
21 Online
OpenStudy (anonymous):
http://math.uc.edu/course/placement/sample/exam/level2.htm
question 4. how would i solve it?
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OpenStudy (anonymous):
-3x^2y(xy^2-2y-1)
OpenStudy (anonymous):
is that what your solving? hah
OpenStudy (anonymous):
Oops, sorry wrong question
OpenStudy (anonymous):
haha its fine. do you know how to solve that one though?
OpenStudy (anonymous):
For question 4, all you are doing this distributing (Multiplying each term inside by outside term)
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OpenStudy (anonymous):
woudld the answer be A?
OpenStudy (anonymous):
\[-3x^2y *\text{xy}^2+-2y*-3x^2y +-1*-3x^2y \]
OpenStudy (anonymous):
I got this, if I didn't make any error:
\[3 x^2 y+6 x^2 y^2-3 x^3 y^3\]
OpenStudy (anonymous):
so it would be b?
OpenStudy (anonymous):
Yes, that would seem so
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OpenStudy (anonymous):
how would i solve it? its just distributiing?
OpenStudy (anonymous):
Yes, just multiply outside term by every term inside the parenthesis
OpenStudy (anonymous):
the -3x^2y i multiple it with everyting?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
when an exponent is being multiplied does it stay the same do i add them together or multiply them?
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OpenStudy (anonymous):
You add them
\[x^a * x^b=x^{a+b}\]
OpenStudy (anonymous):
\[(x^a)^b=x^{a b}\]
OpenStudy (anonymous):
with these exponents though ^2(^2) that would be 4 or would it stay 2?
OpenStudy (anonymous):
do you mean
\[(x^2)^2=x^4\]
OpenStudy (anonymous):
yeah thank you for answering!
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OpenStudy (anonymous):
im probs going to have more questions so feel free to answer more if you want to
OpenStudy (anonymous):
ok