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Mathematics 21 Online
OpenStudy (anonymous):

http://math.uc.edu/course/placement/sample/exam/level2.htm question 4. how would i solve it?

OpenStudy (anonymous):

-3x^2y(xy^2-2y-1)

OpenStudy (anonymous):

is that what your solving? hah

OpenStudy (anonymous):

Oops, sorry wrong question

OpenStudy (anonymous):

haha its fine. do you know how to solve that one though?

OpenStudy (anonymous):

For question 4, all you are doing this distributing (Multiplying each term inside by outside term)

OpenStudy (anonymous):

woudld the answer be A?

OpenStudy (anonymous):

\[-3x^2y *\text{xy}^2+-2y*-3x^2y +-1*-3x^2y \]

OpenStudy (anonymous):

I got this, if I didn't make any error: \[3 x^2 y+6 x^2 y^2-3 x^3 y^3\]

OpenStudy (anonymous):

so it would be b?

OpenStudy (anonymous):

Yes, that would seem so

OpenStudy (anonymous):

how would i solve it? its just distributiing?

OpenStudy (anonymous):

Yes, just multiply outside term by every term inside the parenthesis

OpenStudy (anonymous):

the -3x^2y i multiple it with everyting?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

when an exponent is being multiplied does it stay the same do i add them together or multiply them?

OpenStudy (anonymous):

You add them \[x^a * x^b=x^{a+b}\]

OpenStudy (anonymous):

\[(x^a)^b=x^{a b}\]

OpenStudy (anonymous):

with these exponents though ^2(^2) that would be 4 or would it stay 2?

OpenStudy (anonymous):

do you mean \[(x^2)^2=x^4\]

OpenStudy (anonymous):

yeah thank you for answering!

OpenStudy (anonymous):

im probs going to have more questions so feel free to answer more if you want to

OpenStudy (anonymous):

ok

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