Question

Find dy/dx for the equation x^3-2x^2y+3xy^2=38

Answer 1

could you please rewrite the equation because the part 2x^2y doens't make sense?

Answer 2

it would be written like this:
\[x^3-2x^2y+3xy^2 = 38\]

Answer 3

now that sounds good

Answer 4

\[x ^{3} - 2x ^{2}y + 3xy ^{2} = 38\]

Answer 5

dy/dx=(3x^2)/(4x-3y)