Question

10x^4-19x^2+6=0 solve

Answer 1

use radicals as needed and commas

Answer 2

solve
\[10z^2-19z+6=0\] and then replace z by \[x^2\]

Answer 3

(2x^2- 3 )(5x^2 - 2 ) = 0

Answer 4

substitute x^2=y
hence
10y^2-19y+6=0
19+-7 26 or 12
------= -------
20 20
x= = or - root of these answers hence we get 4 answers

Answer 5

\[(2z-3)(5z-2)=0\]
\[z=\frac{3}{2}\] or
\[z=\frac{2}{5}\]

Answer 6

x^2 = 1.5 , 0.4
take sq roots to get x

Answer 7

xo
\[x^2=\frac{3}{2}\]
\[x=\pm\sqrt{\frac{3}{2}}\]
\[x^2=\frac{2}{5}\]
\[x=\pm\sqrt{\frac{2}{5}}\]

Answer 8

\[(\sqrt{2/5},-\sqrt{2/5}),\sqrt{3/2,}-\sqrt{3/2})\]

Answer 9

would that be correct

Answer 10

yes