write a quadratic equation in the variable x having the given numbers as solutions type the equation in standard form, ax^2+bx+c=0
ax^2+bx+c=0 in standard form?
thatswhat the question asked
what are the given numbers?
quadratic formula
the question is writen as it was given to me
i guess we need the given numbers. i am not trying to give you a hard time, but make sure you understand the question. there is something missing here
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
it asks for a quadratic equation whose solutions are given. you need to know the numbers that are given, otherwise this makes no sense
quadratic formula
say the "given numbers" are 2 and 5. then you write \[(x-2)(x-5)=0\] and if you like multiply out to get \[x^2-7x+10=0\] that is a quadratic equation with the "given" zeros of 2 and 5
ummm...
lol
ax^2+bx+c=0 thats all thats given
it is not "quadratic formula" it is "find the equation with the GIVEN zeros"
ok satellite
solution 2, only solution sorry the paper was cut
@ panther i have seen these questions repeatedly. either there is some mistake in the question, or somewhere there are two numbers given to be the zeros. trust me on this
ok now we got somewhere. the answer is \[(x-2)^2=0\]
i have given you all there was sorry i didnt see it at first
you have to multiply out to get \[x^2-4x+4=0\] and that is your answer
ty
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