Question

solve for all real values of x. (x^2)-9x+9=0

Answer 1

no that is wrong

Answer 2

\[x=\frac{9\pm3\sqrt{5}}{2}\]

Answer 3

method is formula, not way easier. i will write it if you like

Answer 4

9-sqrt45 9+sqrt45
------- or -------
2 2

Answer 5

x^2-9x+9=0
Okay, so we start by using the quadratic formula,
\[(-b \pm \sqrt{b ^{2}-4ac})/2a\]
This gives solutions as follows:
\[9/2 \pm (3/2)\sqrt{5}\]
Hope this helps.
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