How many zeros does the function have? f(x)=-3x^6+2x^4+7x^8-5
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OpenStudy (anonymous):
If you are asking how many complex roots the polynomial has, that would of course correspond to the degree of the polynomial.
To find the real roots is more difficult. It is proven to be impossible to solve for the roots of a polynomial of degree higher than 4 in closed form. You will need to do so numerically with a algorithm like Newton's method.
OpenStudy (anonymous):
Wouldn't there be 8 zeros? Because of the highest exponent?
OpenStudy (anonymous):
8 complex roots yes
OpenStudy (anonymous):
Ok, thank you
OpenStudy (anonymous):
Couldn't I graph it on my calculator and count the x-intercepts?
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OpenStudy (anonymous):
Hello?
OpenStudy (anonymous):
Sure I guess you could do that.
OpenStudy (anonymous):
It looks like there are 2 real roots.
OpenStudy (anonymous):
So for the question, should I put 2 or 8? It just asks how many zeros.
OpenStudy (anonymous):
You could say 2 real roots and 6 complex roots.
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OpenStudy (anonymous):
I thought there were 8 complex roots?
OpenStudy (anonymous):
Hello?
OpenStudy (anonymous):
HELLO????
OpenStudy (anonymous):
Sorry before when I said 8 complex roots I meant 8 complex & real roots. My point is there are always n roots total where n is the degree of the polynomial.