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Mathematics 15 Online
OpenStudy (anonymous):

After a certain drug is injected into a patient, the concentration C of the drug in the bloodstream is monitored. At time t(greater than)0 (in minutes since the injection), the concentration (in mg/L) is given by the equation: C(t)=45t/t^2 +9 What is the eventual concentration of the drug? ______mg/L

OpenStudy (anonymous):

\[\frac{45t}{t^2+9}\] ?

OpenStudy (amistre64):

the eventual concentration? do they specify a time constraint?

OpenStudy (anonymous):

I assume it peaks at certain point

OpenStudy (amistre64):

given that the initial concentration is the most concentrated it can be; unless of course the body starts making more of it :)

OpenStudy (anonymous):

time is greater than 0

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=lim {t+to+infinity}+45t%2Ft^2+%2B9 the limit as t goes to inifinty is either going to be 0 or 9 depending on the original format of the equation

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=lim {t+to+infinity}+45t%2F%28t^2+%2B9%29

OpenStudy (amistre64):

it chopped the links .....

OpenStudy (amistre64):

maybe this version? http://www.wolframalpha.com/input/?i=lim(t+to+infinity)+45t%2F%28t^2+%2B9%29

OpenStudy (amistre64):

that works, the parser doesnt like the { } brackets apparently

OpenStudy (anonymous):

http://tinyurl.com/42ldltb

OpenStudy (anonymous):

so based on these graphs what r we assuming the eventual concentration is in mg/L

OpenStudy (anonymous):

I think it is asking for peak concentration

OpenStudy (amistre64):

if the equation is: \(\cfrac{4t}{t^2}+9\) we would get 9 if the equation is: \(\cfrac{4t}{t^2+9}\) we would get 0

OpenStudy (amistre64):

if its asking for peak concentraion than yeah, my reply would not have any bearing

OpenStudy (anonymous):

its 45t/(t^2+9)

OpenStudy (amistre64):

without knowing what it means by "eventual" concentration; i wouldnt be able to give a definitive answer

OpenStudy (anonymous):

see that is my problem

OpenStudy (amistre64):

i assume it means as time reaches into eternity .... and ive been known to be wrong :)

OpenStudy (amistre64):

if its asking when the concentration reaches a peak value; it would be at t=3, at a value of 15/2 .....

OpenStudy (anonymous):

and or 7.5?

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