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Mathematics 18 Online
OpenStudy (anonymous):

I do not understand how we can have 4 vectors in R^3? It says show that the vectors v_1=(1,1,1), v_2=(1, 1,0), v_3=(1,0,0), v_4=(3, 2, 0) span R^3 but do not form a basis for R^3?

OpenStudy (anonymous):

You don't understand you can have 4 vectors in R^3?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

well, (1,0,0) is in R^3, so is (2,0,0), (0,1,0) and (121,45,22)

OpenStudy (anonymous):

Okay R^3 is like an area and you can have as many vectors as it allows?

OpenStudy (anonymous):

like within the range of it right

OpenStudy (anonymous):

Yes, there are infinitely many vectors in R^3.

OpenStudy (anonymous):

Oh okay so for my question it says show that its a span but do not form a basis

OpenStudy (anonymous):

does that mean that the 4 vectors are dependent of each other?

OpenStudy (anonymous):

For those vectors to be basis of R^3 they have to be independent.

OpenStudy (anonymous):

They don't have to be independent to span R^3.

OpenStudy (anonymous):

Yes so I'd show that they are dependent

OpenStudy (anonymous):

Yeah I was just wondering how'd you show that it's a span of R^3

OpenStudy (anonymous):

I know that if the determinant is non zero then it's a span but it's not a square matrix so I can't do that

OpenStudy (anonymous):

Ok, if you add and subtract those vectors from each other, can you see that you can make the vectors (1,0,0), (0,1,0), (0,0,1) and (3,2,0?)

OpenStudy (anonymous):

ohh so 0(1,1,1)+2(2,2,0)+2(1,0,0)=(3,2,0)?

OpenStudy (anonymous):

oops 0(1,1,1)+2(1,1,0)+2(1,0,0)=(3,2,0)?

OpenStudy (anonymous):

Well, yes, you can make (3,2,0) from the first three vectors, but in fact you can make every vector in R^3. That's easiest to see when you have (1,0,0), (0,1,0), (0,0,1).

OpenStudy (anonymous):

But I don't have (1,0,0), (0,1,0) or (0,0,1)?

OpenStudy (anonymous):

well maybe I do that (1,0,0) but that's it

OpenStudy (anonymous):

sorry for not getting this

OpenStudy (anonymous):

you can get them by adding and subtracting the vectors. v1-v2=(0,0,1) for example.

OpenStudy (anonymous):

Oh I see okay so if I want to make sure something is span of R^n so I check that the vectors make those vectors?

OpenStudy (anonymous):

That's right.

OpenStudy (anonymous):

okay how about like v_1=(4,3) for R^2?

OpenStudy (anonymous):

if you're only given one vector how'd you prove it

OpenStudy (anonymous):

You can't span R^2 with only one vector.

OpenStudy (anonymous):

see that's the thing I'm slightly confused with b/c you said there's an infinite amount of vectors in R^3?

OpenStudy (anonymous):

what happens if you're given only 1 or 2 vectors?

OpenStudy (anonymous):

You need at least the same amount of vectors as the dimension of the vectorspace to span that space. So for R^3 you need at least three vectors.

OpenStudy (anonymous):

at least 3 but you can have more? oh okay that makes a lot more sense!! thanks for all your help!!

OpenStudy (anonymous):

You can have as many as you want to span the space. Not to form a basis though, because they wont be independent.

OpenStudy (anonymous):

haha okay so if you have 4 vectors in R^3 it can possibly span but it won't be linearly independent?

OpenStudy (anonymous):

That's right.

OpenStudy (anonymous):

will it always span? if it's the same amt or greater

OpenStudy (anonymous):

No, for example (1,0,0), (2,0,0), (3,0,0), (4,0,0) doesn't span R^3

OpenStudy (anonymous):

Oh okay thank you so much, you just taught me something I couldn't get for awhile in like 10 minutes!!

OpenStudy (anonymous):

You're welcome.

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