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OpenStudy (anonymous):
(Sq rt 4x+3) = -2 please help
show all work
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OpenStudy (anonymous):
start by raising both sides to the 2nd power this will clear the radical and then you solve for x like normal
OpenStudy (anonymous):
need all steps please, did that and got wrong answer.
OpenStudy (dumbcow):
No solution
the sqrt of a number must be positive
OpenStudy (anonymous):
answer should be "null"
OpenStudy (anonymous):
sq -2= positive 4?! where am i going wrong?
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OpenStudy (anonymous):
raise the -2 to the 2nd power and you get 4
OpenStudy (anonymous):
i have the following: 4x+3=4 , 4x= 1, x= 1/3
OpenStudy (anonymous):
now the radical is removed from the other side because you did that also imaginarly
OpenStudy (anonymous):
1/4 th, sorry.. not 1/3
OpenStudy (dumbcow):
that is correct
so x = 1/4 could be a solution
however sqrt(4) does not equal -2
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OpenStudy (anonymous):
so, if I get an answer.. how is it a null? like the book answer says?
OpenStudy (dumbcow):
by plugging it back into original equation and check if equality holds
if it doesn't then its no solution or "null"
OpenStudy (anonymous):
ohh, right.. i forgot that ty , ty
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