Question

State the y-coordinate of the y-intercept for the function below.

ƒ(x)=x^3-x^2-x+1

Answer 1

when y intercpets, x = 0

so here,


ƒ(x)=x^3-x^2-x+1

ƒ(x)=(0)^3-(0)^2-0+1

ƒ(x)= +1

Answer 2

so the y-coord is 1?

Answer 3

y intercpt is 1.

Answer 4

what y cordiante do u want?

Answer 5

it says state the y-coord of the y-intercept. wouldnt that just be 0?

Answer 6

lol, thats the same thing, they are just confusing u.

y intercpt = 1

y cor = (0,1)

Answer 7

oh lol, thanks

Answer 8

hehe, welks.