Question

Rewrite with rational exponents.

^3sqrt xy^2 z

Answer 1

\[^3\sqrt xy^2 z\] The square root goes all the way across

Answer 2

\[\sqrt[3]{xy^2z}=(xy^2z)^{\frac{1}{3}}\]

Answer 3

btw that is "cube root" not "square root"

Answer 4

oops. Thanks for correcting me :)

Answer 5

\[(^{7}\sqrt{2x ^{4}}y)^{11}\]