{(7 3/8)(23 1/5)} / (7 1/4)
\[7\frac{3}{8}*23\frac{1}{5} \div 7\frac{1}{4}\]
this?
Yes
\[23\frac{3}{5} \]
22 4/5 was what it said the answer was now I have to do another problem for the question. {(6 7/8)(21 3/5)} / (7 3/4)
Here is an example it shows but I have no idea how they get this answer. {(7 1/8)(23 3/5)}/(7 1/2) = 22 2/5
When I get the answer wrong it just gives the same problem with different numbers and you are able to solve it until you get it right
are u doing Mathlab?
I have no idea how they are getting these answers and yes
thts the problem with online schools.
Im using my calc for them. but i also knw how to do them manually. first convert them to improper frac, then solve them!
what's the next prob?
{(6 7/8)(21 3/5)} / (7 3/4)
55/8 * 108/5 / 31/4? is that right?
5940/40 * 4/31?
right.
23760/1240 = 19.161...... then I am lost how do I turn that into a fraction?
try cancelling the frac by 2.
like this? 11880/620 = 1188/62 = 594/31 = that can't be right can it
u r doing it right.
2376/124 = 594/31 = 19 5/31? then rounded to the nearest fifth would be
right.
It has to be rounded to the nearest fifth
19.161290 what fifth? deicaml? sign. fig?
fraction
how can it be a nearest to fifth fraction?
like 19 1/5 I am not sure that's what it says to do
Nope. that must be in decimals.
well it's a word problem about measuring head circumference for a hat and it says to round to the nearest 1/5th of an inch
so there's what 32 cm in an inch right or 32 something
aaah, i did that before! its in Mathlab.. there are same 2 problems!
i wrote that in decialms that time.
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