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Mathematics 24 Online
OpenStudy (anonymous):

anyone know trig?

OpenStudy (saifoo.khan):

Yeas!

OpenStudy (anonymous):

nice

OpenStudy (anonymous):

ok find a1 a2 a3 a4 when you have a subscript n = 2(n+3)!

OpenStudy (anonymous):

a1 is 48 right? the factorial is throwing me off a bit...

OpenStudy (zarkon):

trig?

OpenStudy (anonymous):

well, actually precal... its a math 113 in college.

OpenStudy (zarkon):

\[a_1=48\] as long as the factorial is not supposed to include the 2

OpenStudy (anonymous):

so a2 is going to be 2(5x5x3x2 )

OpenStudy (zarkon):

each college/university uses it own numbering system...math 113 tells me nothing ;)

OpenStudy (anonymous):

(5x4x3x2)*****

OpenStudy (anonymous):

sorry :(

OpenStudy (anonymous):

its the class right before calculus. lol.

OpenStudy (zarkon):

\[a_2=240\]

OpenStudy (anonymous):

ok i just wasnt for sure if the 2 was included, that was my actual problem, but thank you!

OpenStudy (zarkon):

if they wanted the 2 included they should type \[[2(n+3)]!\]

OpenStudy (anonymous):

Thank you ill find out in a minute...

OpenStudy (anonymous):

ok another qustion?

OpenStudy (anonymous):

express the sum using summation notation. use 1 as the lower limit of summation and i for the index of summation

OpenStudy (anonymous):

2+5+8+...+(3n-1)

OpenStudy (zarkon):

\[\sum_{i=1}^{n}(3i-1)\]

OpenStudy (zarkon):

hi myininaya...how's it going :)

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

im done, that was right, the original question that i asked. this website would have been nice at the beginning of the semester.

OpenStudy (zarkon):

good ;)

myininaya (myininaya):

hey

OpenStudy (zarkon):

wheat...barley.. ;)

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