Mathematics
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OpenStudy (anonymous):
anyone know trig?
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OpenStudy (saifoo.khan):
Yeas!
OpenStudy (anonymous):
nice
OpenStudy (anonymous):
ok find a1 a2 a3 a4 when you have a subscript n = 2(n+3)!
OpenStudy (anonymous):
a1 is 48 right? the factorial is throwing me off a bit...
OpenStudy (zarkon):
trig?
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OpenStudy (anonymous):
well, actually precal...
its a math 113 in college.
OpenStudy (zarkon):
\[a_1=48\]
as long as the factorial is not supposed to include the 2
OpenStudy (anonymous):
so a2 is going to be 2(5x5x3x2
)
OpenStudy (zarkon):
each college/university uses it own numbering system...math 113 tells me nothing ;)
OpenStudy (anonymous):
(5x4x3x2)*****
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OpenStudy (anonymous):
sorry :(
OpenStudy (anonymous):
its the class right before calculus. lol.
OpenStudy (zarkon):
\[a_2=240\]
OpenStudy (anonymous):
ok i just wasnt for sure if the 2 was included, that was my actual problem, but thank you!
OpenStudy (zarkon):
if they wanted the 2 included they should type
\[[2(n+3)]!\]
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OpenStudy (anonymous):
Thank you ill find out in a minute...
OpenStudy (anonymous):
ok another qustion?
OpenStudy (anonymous):
express the sum using summation notation. use 1 as the lower limit of summation and i for the index of summation
OpenStudy (anonymous):
2+5+8+...+(3n-1)
OpenStudy (zarkon):
\[\sum_{i=1}^{n}(3i-1)\]
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OpenStudy (zarkon):
hi myininaya...how's it going :)
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
im done, that was right, the original question that i asked. this website would have been nice at the beginning of the semester.
OpenStudy (zarkon):
good ;)
myininaya (myininaya):
hey
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OpenStudy (zarkon):
wheat...barley..
;)