okay...the table lists data regarding the avg saleries of athletes in the years 1991 ($272,000) and 2001 ( 1,450,000). What is the linear function that fits the data S(x) =? What is the predicted avg salary for 2005? For 2010?
what if i say thats easy?
I would tell you that you are nuts. LOL
HAHA.
You are funny...that is not easy.
oh crap, let me get my glasses on...
HAHA1.
should i solve futher?
further*
use slope formula \[m = \frac{y2-y1}{x2-x1} = \frac{1450000 - 272000}{2001-1991} = \frac{1178000}{10} = 117800\]
yea, what is the predicted salary for 2005 and for 2010?
wow, dumbcow...you are intense.
So 117, 800 is the salary for what year?
that is the slope, it increases by that amout each year S(x) = 272,000 + 117,800x where x is years after 1991 2005: x = 14 2010: x =19
Okay, that would be for 14 years right?
117,800 would be for the 14 years????
So what would it be for the 19 years?
saifoo how do you get 109,800 for slope? plug in the 14,19 into S(x)
Come on..somebody please answer....
Oh wait.. my bad, lol.
@dumbunny S(x)=272,000 + 117,800x plug in 14 and 19 for x
S(x) = 272000+1450,000(14) 20572000 S(x) = 272000+1450,000(2010-1991) = 27822,000
here u go!
Hey! I see the athlete salary question now! Seems I came in a little late :/
Oh hmm.
dang, I wish I could get an answer to that athlete question.
I see S(x) = 272,000 + 117,800....thats as far as I got.
haha c'mon you can figure it out. you know that for 2005, x = 14 and for 2010, x = 19 now where do you put the x in the equation? after the slope, right? the slope is 117,800 so multiply x(insert number here) by the slope then add 272,000
No, I can't and I can't move to the next question until I get this one right. So I am pretty much screwed.
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