Consider the solid S described below.
The base of S is a circular disk with radius 2r. Parallel cross-sections perpendicular to the base are squares.
Find the volume V of this solid.

Question

anonymous · Answer

since all the cross sections are squares, the height of the solid, known as the "cylinder" is equal in length to the circumference of the base. Thus the volume is= pi(2r)^2*2r=pi*4r^2*2r=pi*8r^3

anonymous · Answer

for some reason this answer doesnt work...

anonymous · Answer

well, i'm probably wrong. I think this has to do with calculus and finding integrals. Is this problem for calculus?

anonymous · Answer

yes, this is calculus 2

anonymous · Answer

try this, it can help http://answers.yahoo.com/question/index?qid=20101007174749AAZyxDi