How can I find the domain and range of 2sin(4x+pi)+3? Logic, please?
as for the range you know that sinx lies between -1 and 1..
so you can use these extreme values to get your range as [1,5]..
Sorry, your last comment lost me ><
what happened Denebel?
joe again d 2 of us.. lol
lolol
joe the domain is all real numbers?
yes
:)
So the general graph of a sin function... makes the range to be between -1 and 1.. yeah.. so does the amplitude of 2 have anything to do with the range?
If it did not have the +3 vertical shift (that is correct right? it is a vertical shift?) then the range would be between -2 and 2?
the amplitude is 1 and it has nothing to do in this question.... you just take the max n min value
yes, you start with [-1,1], that 2 thats multiplying sin will change it to [-2,2]. Then we are adding 3 to all of that, so it will be [-2+3, 2+3] = [1,5], what akshay got :)
if u multiply 2 den yes amplitude is 2.. then it will be [-2,2] joe has done d job though.lol
Oh, I see. So for all sin/cos/csc/sec functions, the domain should be all real numbers, right? Only tan functions is not all real.
right.
er, tan and cot.
cot too
i knew i forgot something lol
lol
Oh okay. Thank you :)
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