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Mathematics 19 Online
OpenStudy (anonymous):

How can I find the domain and range of 2sin(4x+pi)+3? Logic, please?

OpenStudy (akshay_budhkar):

as for the range you know that sinx lies between -1 and 1..

OpenStudy (akshay_budhkar):

so you can use these extreme values to get your range as [1,5]..

OpenStudy (anonymous):

Sorry, your last comment lost me ><

OpenStudy (akshay_budhkar):

what happened Denebel?

OpenStudy (akshay_budhkar):

joe again d 2 of us.. lol

OpenStudy (anonymous):

lolol

OpenStudy (akshay_budhkar):

joe the domain is all real numbers?

OpenStudy (anonymous):

yes

OpenStudy (akshay_budhkar):

:)

OpenStudy (anonymous):

So the general graph of a sin function... makes the range to be between -1 and 1.. yeah.. so does the amplitude of 2 have anything to do with the range?

OpenStudy (anonymous):

If it did not have the +3 vertical shift (that is correct right? it is a vertical shift?) then the range would be between -2 and 2?

OpenStudy (akshay_budhkar):

the amplitude is 1 and it has nothing to do in this question.... you just take the max n min value

OpenStudy (anonymous):

yes, you start with [-1,1], that 2 thats multiplying sin will change it to [-2,2]. Then we are adding 3 to all of that, so it will be [-2+3, 2+3] = [1,5], what akshay got :)

OpenStudy (akshay_budhkar):

if u multiply 2 den yes amplitude is 2.. then it will be [-2,2] joe has done d job though.lol

OpenStudy (anonymous):

Oh, I see. So for all sin/cos/csc/sec functions, the domain should be all real numbers, right? Only tan functions is not all real.

OpenStudy (anonymous):

right.

OpenStudy (anonymous):

er, tan and cot.

OpenStudy (akshay_budhkar):

cot too

OpenStudy (anonymous):

i knew i forgot something lol

OpenStudy (akshay_budhkar):

lol

OpenStudy (anonymous):

Oh okay. Thank you :)

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