Question

determine the derivative of the following functions x-squared over x-1

Answer 1

\[\frac{d}{dx}\frac{x^2}{x-1}=\frac{x^2-2x}{(x-1)^2}\]\]

Answer 2

need the steps? straight up quotient rule. use
\[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\]
\[f(x)=x^2,f'(x)=2x,g(x)=x-1,g'(x)=1\] and plug them in

Answer 3

satellite73 derivatives have its step by step process right...

Answer 4

it should be \[x^2/x-1\]

Answer 5

only work is
\[g'f-f'g=(x-1)2x-x^2\times 1=x^2-2x\]\]

Answer 6

that is the only "step" you need really. just the algebra in the numerator

Answer 7

then \[x \over (x+Deltax)-1\]

Answer 8

together with \[x \over x-1\]