Question

Find the x-coordinates of the points of intersection of the curves y = x^2 + 1 and y = 2x^2 - 3.

Answer 1

this is where those system of equations work from algebra should kick in :)

Answer 2

intersection : x^2+1=2x^2-3
x^2+1-2x^2+3=0
-x^2=-4
x^2=4
x=sqr4
x=+-2

Answer 3

y = x^2 + 1 ; *-1
y = 2x^2 - 3


-y =-x^2 -1
y = 2x^2 - 3
------------
0 = x^2 -4 ; to wit, x^2 has to be 4.

+- 2 would be appropriate