length of a rectangle is 6yd longer than its width. If the perimeter of the rectangle is 48 yd, find its area
w + 6 = l 2w +2l = 48 Solve simultaneously
Wanna work on this together?
l = 6 + w 2(6+w) + 2w = 48 sove to get l and w then area is simply l*w
still dont get it
Then let's work together, shall we? First of all, what letter do you want to use for our width?
Because you know the length is 6 units longer than the width you know that: width + 6 = length
or w+6 = l
yep i get that
Alright, now tell me what perimeter equals.
ok, then you know that the perimeter of a rectangle is 2* width +2* length
Like in general, what does perimeter mean?
adding up all sides
alright, so an equation for the perimeter (which we know is 48) would be....?
Excellent. So L + L + W + W = perimeter, right? Or if we combine like terms, 2L + 2W = perimeter. Does that make sense?
If it doesn't feel free to let me know. I can explain it more deeply.
makes sense!
Sweet! Ok, so in the beginning we decided that w+6 = L L is equal to (w+6) And now we want to say that 2L + 2W = perimeter. Do you know what L is equal to?
(We don't know the exact number it equals, but give me a formula that tells us how big L is)
-5?
We haven't been told anything about that. Though, -5 would be a false value, as we can't have negative values. Hint: I actually gave you the answer in the same post where I asked you "Do you know what L is equal to?" Look carefully and you'll see what "L is equal to".
w+6
Excellent! So, here's the thing: Anytime you see L in another formula, you can completely replace the L with (w+6) So, what do we do here: 2L + 2W = perimeter
(Hint: get rid of that L by replacing it)
So, what did you get? I can't help if you don't reply. :P
l = 6 + w 2(6+w) + 2w = 48 12+2w+2w=48 12+4w=48 -12 -12 4w=36 /4 /4 w=9 yd l=15 yd 9*15=135 yd^2 I am pretty sure that is your answer c:
Width=x Length=x+6 Parameter=2(x+x+6)=48 ==>x=9 and x+6=15 Area=9*15=135
"2(6+w) + 2w = 48" That is what I was hoping you would go for.
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