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x^2-4x+2=0 using the quadratic fomula solve this
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x=-b+-sq rt b^2-4ac/2a ax^2+bx+c=0
so a=1, b=4 and c=2 plug into the first equation and solve
\[x=b \pm \sqrt{b ^{2-4ac}}/2a\]
plug the values into the previous equation and solve
just so the equation is a little clearer: \[x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}\]
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\frac{numerator}{denominator}
what did you get as an anwer
answer sorry
use joe maths equation it is clearer and plug in so a=1, b=4 and c=2
-3.414213562, -0.5857864376 are your answers
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